I have searched and found 2 methods of finding volume using integration :
- considering a small cylindrical element and integrating that over the radius
- considering a small circle element and using the relation
x^2 + y^2 = r^2and integrating it over thez-axis.
I was trying to find the integration by considering a small circle element (with radius r) and using the relation r = R cosθ where R is the radius of the sphere / hemisphere.
So I was thinking of calculating the volume of the hemisphere by integrating the π R^2 cos^2θ dθ from 0 to π/2. Is this method right? And how will the integration be like?
I do not like the "consider a small element" approach physicists often use, as it is not very intuitive and can easily produce errors. In this case you can just use the usual transformation of integrals: $\renewcommand{\phi}{\varphi}$
$$ \int_{\Omega} f(y) dy = \int_{\phi^{-1}(\Omega)} f(\phi(x)) |\det D\phi(x)| dx $$
Where $\varphi : \Omega \to \phi(\Omega) \subseteq \mathbb R^{n}$ is transformation of the coordinate systems and $D\phi : \Omega \to \mathbb R^{n\times n}$ is the corresponding Jacobi matrix.
So in your case all you have to do is set $f:\equiv 1$ and write down your transformation $\phi$. Then $|\det D\phi(x)|$ is the expression you are looking for, and the above equation simplifies to
$$Vol(\Omega) = \int_{\Omega} 1dy = \int_{\phi^{-1}(\Omega)} |\det D\phi(x)| dx $$