For a given $\triangle ABC$, construct a $\triangle A'B'C'$ that has $\triangle ABC$ as its extouch triangle

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For a given $\triangle ABC$, construct a $\triangle A'B'C'$, so that the $\triangle ABC$ is the extouch triangle of $\triangle A'B'C'$.

The extouch triangle is the triangle formed by the points of tangency of the excircles with their corresponding sides.

Thanks!