If direction cosines of $AB = ( L_1 , M_1,N_1)$ and direction cosines of $AC = (L_2,M_2,N_2)$ then direction ratio of bisector of $∠BAC$ are?
2026-04-02 01:40:35.1775094035
Formula to find angular bisector when DC's are given
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As absolute position does not matter in this case, you can take $A=(0,0,0)$ so that $B = ( L_1 , M_1,N_1)$ and $C = (L_2,M_2,N_2)$. The angle bisector is then line $AD$, where $D$ is the midpoint of $BC$, and its direction ratio is $$ (L_1+L_2):(M_1+M_2):(N_1+N_2). $$