Could someone tell me if I've worked this out right? I'm unsure of the process, especially the final parts where I convert it to a sinc function.
Please let me know if I've made mistakes anywhere else too.
Could someone tell me if I've worked this out right? I'm unsure of the process, especially the final parts where I convert it to a sinc function.
Please let me know if I've made mistakes anywhere else too.
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The mistake on the last step: $$ \frac{6}{\sqrt{2\pi}} \left[ \frac {\sin^2\frac{3\omega}2}{\frac{3\omega^2}2} \right] = \frac{6}{\sqrt{2\pi}} \left[ \frac {\sin^2\frac{3\omega}2}{\frac{2}{3}\left(\frac{3\omega}2\right)^2} \right] = \frac{9}{\sqrt{2\pi}} \left[ \frac {\sin\frac{3\omega}2}{\frac{3\omega}2} \right]^2 = \frac{9}{\sqrt{2\pi}} {{\rm sinc}^2\frac{3\omega}2} $$