I'm trying to solve a PDE with a spectral method.
The PDE has a fractional Laplacian... $\Delta^s$.
In regards to a numerical implementation, will the "s" term simply become the exponent of the "differentiation matrices".
$\widehat{(-\Delta)^s f}(\xi) = |\xi|^{2s} \hat f(\xi).$
Or is it not so simple?