The image below is part of Fredholm theory in A. Friedman's book. This is to prove $$\dim(\ker(\lambda-T))=\dim(\ker(\lambda-T)^*).$$ I don't understand how to reach the highlighted part: $\lambda x-Tx=0$
Could anybody help? Thanks.
The image below is part of Fredholm theory in A. Friedman's book. This is to prove $$\dim(\ker(\lambda-T))=\dim(\ker(\lambda-T)^*).$$ I don't understand how to reach the highlighted part: $\lambda x-Tx=0$
Could anybody help? Thanks.
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$\lambda x-T(x)=\sum_{i=1}^{i=n} x_i^*(x)y_i$. It is an element of $Vect(y_1,...,y_n)$ The author shows that $x_i^*(x)=0, i=1,...,n$ this implies that $\lambda x-T(x)=0$ since its coordinates are zero in the basis $(y_1,...,y_n)$ of $Vect(y_1,...,y_n)$.