Functions - The line y=mx cuts the graph of y=f(x) in two distinct places. Find all possible values of m.

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Functions

I understand part a: f(x)=-4|x-6|+7, but for part b I tried to solve it simultaneously and formed a quadratic equation and then used the discriminant b^2-4ac, and I got m<-28/25, m>28/25, but the answer is -4<m<7/6. Is there an error in my calculations or in the way I solved it?

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I would solve it geometrically.

$m$ in $y=mx$ is a line with slope $m$ and it passes through the origin.

I would place my ruler fixed at the origin and rotate it around, we can observe two interesting slope.

  • If our line is steeper than the line connecting the origin and the vertex, the number of intersection is $0$. Hence find the slope for the line connecting $(0,0)$ and $(6,7)$.

  • As I further reduce my gradient, it will cut at two places until my line is parallel to the decreasing line. Hence find the slope the line connecting $(6,7)$ and $(9,-5)$.

Our range of interest of $m$ is between the two values.