In our algebra lecture we discussed the following corollary that came after the Theorem of Galois Correspondence:
Corollary: Every increasing sequence of fields $K \subseteq M_1 \subseteq \dots \subseteq M_n \subseteq L$ corresponds to a decreasing sequence of subgroups of $G:=Gal(L:K)$: $$Gal(L:K) \geq Gal(L:M_1) \geq \dots \geq Gal(L:L)$$
Now here $Gal(L:K)$ denotes all isomorphisms of $L$ that are the identity on $K$, i.e. the galois group of $L$ over $K$. $Gal(L:K)$ is assumed to be finite, normal and separable.
But our proof only has these two steps
Proof:
$L:M_1$ is finite, seperable and normal
$M_{i+1}$ is a intermediate field
I do not know how one then has proven the corollary. Thanks a lot in advance!
$L/K$ is a finite extension. For any subgroup $G \le Gal(L/K)$ let the fixed field $$L^G = \{ x \in L, \forall g \in G, g x = x\}$$
The Galois correspondence follows from :
That to $K \subseteq M_1 \subseteq \dots \subseteq M_n \subseteq L$ we can associate the decreasing sequence of subgroups $Gal(L:K) \geq Gal(L:M_1) \geq \dots \geq Gal(L:L)$ is always true, no matter that $L/K$ is Galois or not. The point is that this is a bijection only when $L/K$ is Galois.