Game theory: Is there always only one dominant strategy?

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I get the impression that there are two classes of games, ones that have been solved and for whom a dominant strategy exists, and ones that have not been solved and for whom a myriad of strong but not necessarily dominant strategies exist.

Is it ever the case that a game has more than one non-equivalent dominant strategy? Or do all cases of games with multiple strong strategies belong to the set of games that have not been solved?

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One cannot have two strictly dominant strategies $\sigma_i$ and $\sigma_i'$ because as $\sigma_i$ is dominant, for all opposing strategies tuples $\sigma_{-i}$: $$ u_i(\sigma_i, \sigma_{-i}) > u_i(\sigma_i', \sigma_{-i}) $$ but as $\sigma_i'$ is dominant, for all $\sigma_{-i}$: $$ u_i(\sigma_i', \sigma_{-i}) > u_i(\sigma_i, \sigma_{-i}) $$ which poses a contradiction. If you mean 'weakly dominant,' so long as your definition of weak dominance is standard (i.e. requires at least one strict comparison), the same argument holds.