For $\theta$ = 2
$\Gamma$($\theta) ^2$ = [(2-1)!]$^2$ = 1
or
$\Gamma$($\theta) ^2$ = (2$^2$-1)! = 3
Which one is correct?
2026-03-25 12:21:28.1774441288
Gamma Function with Square
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Since $\Gamma(n)=(n-1)!,$ and since $\Gamma(\theta)^2 = [\Gamma(\theta)]^2,$ then when $\theta=2,$ we have
$$\Gamma(2)^2 =[(2-1)!]^2=1.$$