Generating function for the partition function

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Could someone explain what is the reasoning behind the following equality? Or maybe direct me to a proof of the following equality?

$$\sum_{n=0}^{\infty}p(n)x^n = \prod_{k=1}^{\infty}(1-x^k)^{-1}$$ where $\sum_{n=0}^{\infty}p(n)x^n$ is the generating function for the partition function.

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For the basic generating functions in term of $(1 - x^k) ^ {-1}$, we can write them out as a infinite sum.

$(1 - x) ^ {-1}$ = $1 + x + x^2 + x^3 + ....$

$(1 - x^2) ^ {-1}$ = $1 + x^2 + x^4 + x^6....$

$(1 - x^3) ^ {-1}$ = $1 + x^3 + x^6 + x^9....$

and so on.

So $\prod(1 - x^k) ^ {-1}$ is just an infinite product of ($1 + x + x^2 + x^3 + ....$)( $1 + x^2 + x^4 + x^6....$)($1 + x^3 + x^6 + x^9....$)....

The for each power term $x^n$, there is a corresponding coefficient p(n). And we need to sum up all these power terms.