The following boolean expression in CNF form
$$ (x \lor y) \land (x \lor \lnot z) $$
Has been mapped into the Karnaugh map below
\begin{array}{| c | c | c | c | c |} \hline - & yz & y\lnot z & \lnot y \lnot z & \lnot y z \\ \hline x & 1 & 1 & 1 & 1 \\ \hline \lnot x & 0 & 1 & 0 & 0 \\ \hline \end{array}
How can I get the DNF from this Karnaugh map?
Any covering that includes the 1s and nothing else will give you a correct DNF.
So you could do each of the 5 individually:
$$xyz \lor xyz' \lor xy'z' \lor xy'z \lor x'yz'$$
Or you could do the top left 2, top right 2, and bottom 1:
$$xy \lor xy' \lor x'yz'$$
Or you could do the entire top row and the entire second column:
$$x \lor yz'$$
Which is the minimal DNF.