Give a derivation of the following formal theorems:

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Show, φ, (φ $\Rightarrow$ ψ), (φ $\Rightarrow$$\Rightarrow$ θ)) $\vdash$ θ

Here is my answer, please let me know if I'm doing this correctly!

  1. φ $\qquad$$\qquad$$\qquad$< Hypothesis 1>
  2. φ $\Rightarrow$ ψ $\qquad$$\qquad$ < Hypothesis 2>
  3. φ $\Rightarrow$$\Rightarrow$ θ)$\qquad$< Hypothesis 3>
  4. ψ $\Rightarrow$ θ $\qquad$$\qquad$ <1,3 + Equanimity>
  5. φ $\Rightarrow$ θ $\qquad$ $\qquad$<2,4 + Transitivity>
  6. θ $\qquad$$\qquad$$\qquad$<1,5 + Equanimity>
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Your proof is correct.

Well, the names are unfamiliar, but the steps are valid inferences.

"Equanimity" appears to be "Modus Ponens" and "Transitivity" is "Hypothetical Syllogism".


You may also do it without "Transitivity", if you wish.

  1. $φ\qquad \qquad \qquad~~$< Hypothesis 1>
  2. $φ \to ψ \qquad\qquad$ < Hypothesis 2>
  3. $φ \to (ψ \to θ)\quad~$< Hypothesis 3>
  4. $ψ \qquad\qquad\qquad$ <1,2 + Equanimity>
  5. $ψ \to θ \qquad\qquad$ <1,3 + Equanimity>
  6. $θ \qquad\qquad\qquad$ <4,5 + Equanimity>