I can't think of a subset that makes $f$ a bijection.
So far, I think the subset should have one constant number, like $(x, n)$ where $n$ is fixed, but this won't cover all positive integers?
$$f : \mathbb{N}^2 \to \mathbb{Z}.$$
I can't think of a subset that makes $f$ a bijection.
So far, I think the subset should have one constant number, like $(x, n)$ where $n$ is fixed, but this won't cover all positive integers?
$$f : \mathbb{N}^2 \to \mathbb{Z}.$$
Copyright © 2021 JogjaFile Inc.