Given: $\log_a 2 = 0.69, \log_a 3 = 1.10$ and $ \log_a 5 = 1.61$, how can you solve $\log_a 30 ? $

Question

Given: $$\log_a 2 = 0.69, \log_a 3 = 1.10, \log_a 5 = 1.61$$ How can you solve $$\log_a 30 = ?$$

I am doing Schaum's pre-calculus book, and I can do all exercice in the chapter, but I have no idea how to find this solution. Anyone can help?

Answer 1

Hint: $2\times3\times5 = 30$

And $\log(xyz) = \log(x) + \log(y) + \log(z)$