Given two numbers a, b transcendent and algebraically dependent and c one number, if a, b and c are algebraically dependent, then c is transcendent

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Given two numbers a, b transcendent and algebraically dependent and c one number, if a, b and c are algebraically dependent, then c is transcendent. Is this result true? If so, how can I prove it?

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This is false. Indeed, take $(a,b,c)=(\pi,2\pi,0)$. Then $2a−b=c$, however $c$ is not transcendental.