Let $f:\Bbb{R}^2\longrightarrow \Bbb{R}$ and $f(x,y)=i.$
So will the graph of this function be x-y plane? Where it has 3 axis: x and y are real axis and z is the imaginary axis? Basically somewhat like Is this the Graph
I am in highschool and I was just curious because my teachers'answer wasn't satisfactory enough.
The best way I can understand your function is from $\mathbb{R}^2$ to $\mathbb{C}$. Both are two-dimensional vector spaces over $\mathbb{R}$, so the graph lies in the four-dimensional space $\mathbb{R}^2 \times \mathbb{C}$. It is $$ A = \left\{(x,y,i) \mid x,y \in \mathbb{R} \right\} $$ It is a two-dimensional affine plane lying in four-dimensional space.
If you ignore one of those dimensions, you might be able to “see” the graph better. Replace $\mathbb{C}$ with $\mathbb{R}$ and $i$ with $1$. The graph of $f(x,y) = 1$ lies in three-dimensional space, and it's just the $xy$-plane shifted “up” by one unit. The graph of your complex $f$ is the same $xy$-plane shifted one in the $i$ direction.