graph of $z=2x+y$

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The usual technique using traces where one variable is set to 0 does not seem to work here since I get all 0's and so where do the intersections meet?

I looked in my calc. book and the technique they use they drop 0 in two variables at a time and get the intersection of the three points where each point is gotten by setting the other two variables 0. I get all 0's in this case too so that does not help either. Can someone help me graph this? My goal is to sketch the level curves to this equation but I must first sketch z= 2x + y. Then I can set z = 0 , 1 and so forth and the plane for each of the equations should intersect the graph of z=2x + y. I believe. Thank you !!

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This is simply a rectangular graph through the origin,as dictated by the level curves 2x + y= 0 , 2x-z =0 and y-z =0. The resulting surface should look like this:

enter image description here