If we have an absolute equation like this one: $$|x-1|+|x+1|=4$$ do I read it as $$|x-1|+|x+1|=y$$ or is it actually: $$|x-1|+|x+1|-4=y$$ The graphs are different so I'm confused which one is the right path to follow if I want to graph the function.
Also, if we have a normale equation like $$3x-2=4$$ do I still need to move the 4 over to the left side so it looks like a function $$3x-6=y$$ so I can graph it, or does it stay on the right side and is ignored when I am graphing my function $$3x-2=y$$?
If you only have one variable you can‘t graph it, because the graph (the line) represents the infintely many solutions for the equation.
Exmaple: $2x+4y=3$ reform it: $y={3-2x \over 4}$, which you can graph.
If you only have one variable there are probably finitely many solutions (values for x that satisfy the equation). If x is bigger than 0, the equation simplifies to:
$(x-1)+(x+1)=4$
$2x = 4$
$x = 2$
So $x=2$ satisfies the equation and is a solution to it.
If x is smaller than 0, the equation reads:
$-(x-1)-(x+1)=4$
$-2x = 4$
$x = -2$
So the other solution is $x=-2$.
That‘s how you can find the values for x, so that the equation with absolute values is true.
You can‘t graph it, because there are only two solutions and the axes would stand for two variables.