The Baumslag-Solitar groups are defined by
$$G=BS(m,n)=\langle a,b: ba^{m}b^{-1}=a^{n}\rangle\,,$$
where $m,n$ are integers.
My question is: Is there a linear action of $G=BS(1,2)$ over $\mathbb{R}^{2}$ ?
The Baumslag-Solitar groups are defined by
$$G=BS(m,n)=\langle a,b: ba^{m}b^{-1}=a^{n}\rangle\,,$$
where $m,n$ are integers.
My question is: Is there a linear action of $G=BS(1,2)$ over $\mathbb{R}^{2}$ ?
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Yes, the matrices $\begin{bmatrix}2&0\\0&1\end{bmatrix}$ and $\begin{bmatrix}1&1\\0&1\end{bmatrix}$ generate a copy of $BS(1,2)$. So this gives an action on $\mathbb{R}^2$.