Question

What is the name of this method?

score 56 · Answer 1 · 2026-04-11 12:43:05

56

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What is the name of this method?

Published on 11 Apr 2026 - 12:43

score 168 · Answer 2 · 2026-04-16 20:26:11

168

Views

If $x^{x^{x+1}}=\sqrt{2}$, then evaluate $x^{x^{p}}$, where $p = 2x^{x+1}+x+1$

Published on 16 Apr 2026 - 20:26

score 140 · Answer 3 · 2026-04-14 14:33:27

140

Views

Integer solution for $2^{3p}+2^{4q}=2^{5r}$

Published on 14 Apr 2026 - 14:33

score 184 · Answer 4 · 2026-04-24 13:34:41

184

Views

Ambiguity in product of all $n$th roots of unity

Published on 24 Apr 2026 - 13:34

score 54 · Answer 5 · 2026-04-09 18:41:38

54

Views

Need help in solving an exponential equation

Published on 09 Apr 2026 - 18:41

score 68 · Answer 6 · 2026-04-16 04:21:23

68

Views

Exponents, versus Exponentials, versus Exponential Functions. Splitting hairs on definitions.

Published on 16 Apr 2026 - 4:21

score 121 · Answer 7 · 2026-04-16 16:29:03

121

Views

Simplifying $\left(\frac{1}{2}\right)^{-1/2}+\left(\frac{3}{2}\right)^{-3/2}+\left(\frac{5}{2}\right)^{-5/2}$

Published on 16 Apr 2026 - 16:29

score 84 · Answer 8 · 2026-04-16 15:47:11

84

Views

2 to the power of a matrix

Published on 16 Apr 2026 - 15:47

score 205 · Answer 9 · 2026-04-13 02:50:09

205

Views

Why is (virtually) anything raised to $0$th power equal to $1$?

Published on 13 Apr 2026 - 2:50

score 188 · Answer 10 · 2026-04-16 06:13:53

188

Views

Trying to show that $(2^{i_k} - 3^k)u - 3^{k-1} - \sum\limits_{s=1}^{k-2}3^{k-1-s}2^{i_s}$ is not equal to a power of $2$.

Published on 16 Apr 2026 - 6:13

score 190 · Answer 11 · 2026-04-12 20:28:19

190

Views

Why does any non-zero expression raised to the power of 0 equal 1?

Published on 12 Apr 2026 - 20:28

score 29 · Answer 12 · 2026-04-10 18:23:17

29

Views

Is there a shorthand function for this repetitive equation

Published on 10 Apr 2026 - 18:23

score 66 · Answer 13 · 2026-04-15 11:33:35

66

Views

Is $1^{1/0}= 1?$

Published on 15 Apr 2026 - 11:33

score 112 · Answer 14 · 2026-04-15 16:52:48

112

Views

Why is the following for $B= A^x -(A-1)^x-(A-2)^x-(A-3)^x...(A-n)^x$ as long as $B ≥ 0$?

Published on 15 Apr 2026 - 16:52

score 191 · Answer 15 · 2026-04-14 23:22:22

191

Views

Collatz Conjecture: Reasoning about the upper limit for the maximum odd integer in a collatz cycle

Published on 14 Apr 2026 - 23:22

List Question

What is the name of this method?

If $x^{x^{x+1}}=\sqrt{2}$, then evaluate $x^{x^{p}}$, where $p = 2x^{x+1}+x+1$

Integer solution for $2^{3p}+2^{4q}=2^{5r}$

Ambiguity in product of all $n$th roots of unity

Need help in solving an exponential equation

Exponents, versus Exponentials, versus Exponential Functions. Splitting hairs on definitions.

Simplifying $\left(\frac{1}{2}\right)^{-1/2}+\left(\frac{3}{2}\right)^{-3/2}+\left(\frac{5}{2}\right)^{-5/2}$

2 to the power of a matrix

Why is (virtually) anything raised to $0$th power equal to $1$?

Trying to show that $(2^{i_k} - 3^k)u - 3^{k-1} - \sum\limits_{s=1}^{k-2}3^{k-1-s}2^{i_s}$ is not equal to a power of $2$.

Why does any non-zero expression raised to the power of 0 equal 1?

Is there a shorthand function for this repetitive equation

Is $1^{1/0}= 1?$

Why is the following for $B= A^x -(A-1)^x-(A-2)^x-(A-3)^x...(A-n)^x$ as long as $B ≥ 0$?

Collatz Conjecture: Reasoning about the upper limit for the maximum odd integer in a collatz cycle

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