Question

Integral closure and $\bigcap \mathfrak{a}^n$

score 78 · Answer 1 · 2026-02-23 13:00:46

78

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Integral closure and $\bigcap \mathfrak{a}^n$

Published on 23 Feb 2026 - 13:00

score 1.4k · Answer 2 · 2016-06-24 11:27:19

1.4k

Views

Irreducible elements for a commutative ring that is not an integral domain

Published on 24 Jun 2016 - 11:27

score 223 · Answer 3 · 2016-06-26 10:42:17

223

Views

Polynomial ring, ideals and Spec

Published on 26 Jun 2016 - 10:42

score 318 · Answer 4 · 2016-06-26 13:31:33

318

Views

Let $D$ be a UFD. If an element of $D$ is not a square in $D$ then is it true that it is not a square in the fraction field of $D$?

Published on 26 Jun 2016 - 13:31

score 128 · Answer 5 · 2016-06-26 13:48:30

128

Views

If $R$ is an integral domain with unity having only finitely many subdomains (not necessarily with unity), then is $R$ finite?

Published on 26 Jun 2016 - 13:48

score 540 · Answer 6 · 2013-04-28 13:34:36

540

Views

If $R$ is integral over $S$, then $\operatorname{Frac}(R)/\operatorname{Frac}(S)$ is finite extension of fields

Published on 28 Apr 2013 - 13:34

score 540 · Answer 7 · 2013-06-12 12:33:21

540

Views

Question on Galois extension of field of fractions

Published on 12 Jun 2013 - 12:33

score 2.8k · Answer 8 · 2013-06-14 14:51:38

2.8k

Views

Why ring with only even numbers is not an integral domain?

Published on 14 Jun 2013 - 14:51

score 214 · Answer 9 · 2013-08-28 09:44:43

214

Views

$R[x]$ can be an integral extension of $R$?

Published on 28 Aug 2013 - 9:44

score 193 · Answer 10 · 2013-09-23 03:42:32

193

Views

$\varphi: F[X] \rightarrow R'$ an integral domain, then $\ker \varphi$ is maximal or $(0)$

Published on 23 Sep 2013 - 3:42

score 426 · Answer 11 · 2013-10-01 16:00:49

426

Views

Integral domain is ufd iff atomic and gcd domain

Published on 01 Oct 2013 - 16:00

score 877 · Answer 12 · 2013-10-08 15:16:17

877

Views

$P$ is a prime ideal, and $ R/P$ has no nilpotent elements. Then $R/P$ is a domain.

Published on 08 Oct 2013 - 15:16

score 1.8k · Answer 13 · 2013-10-18 20:41:19

1.8k

Views

Integral domain in complex numbers.

Published on 18 Oct 2013 - 20:41

score 8.1k · Answer 14 · 2013-10-28 19:42:02

8.1k

Views

Proving that a ring is not a Principal Ideal Domain

Published on 28 Oct 2013 - 19:42

score 142 · Answer 15 · 2013-10-31 19:43:35

142

Views

The integral closure of Bezout domains in arbitrary field extensions is Prüfer?

Published on 31 Oct 2013 - 19:43

List Question

Integral closure and $\bigcap \mathfrak{a}^n$

Irreducible elements for a commutative ring that is not an integral domain

Polynomial ring, ideals and Spec

Let $D$ be a UFD. If an element of $D$ is not a square in $D$ then is it true that it is not a square in the fraction field of $D$?

If $R$ is an integral domain with unity having only finitely many subdomains (not necessarily with unity), then is $R$ finite?

If $R$ is integral over $S$, then $\operatorname{Frac}(R)/\operatorname{Frac}(S)$ is finite extension of fields

Question on Galois extension of field of fractions

Why ring with only even numbers is not an integral domain?

$R[x]$ can be an integral extension of $R$?

$\varphi: F[X] \rightarrow R'$ an integral domain, then $\ker \varphi$ is maximal or $(0)$

Integral domain is ufd iff atomic and gcd domain

$P$ is a prime ideal, and $ R/P$ has no nilpotent elements. Then $R/P$ is a domain.

Integral domain in complex numbers.

Proving that a ring is not a Principal Ideal Domain

The integral closure of Bezout domains in arbitrary field extensions is Prüfer?

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