Question

How to solve the integral equation $f(x) = \int_0^x f(x-y)k(x,y)dy+g(x)$ for $f(x)$?

score 282 · Answer 1 · 2026-03-20 09:02:05

282

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How to solve the integral equation $f(x) = \int_0^x f(x-y)k(x,y)dy+g(x)$ for $f(x)$?

Published on 20 Mar 2026 - 9:02

score 100 · Answer 2 · 2026-03-23 06:21:37

100

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Solving for $f\left(\sqrt{x^2+z^2}\right)$ given $g(z)=\int_{-\infty}^{+\infty}{\left(f\left(\sqrt{x^2+z^2}\right)\frac{1}{\sqrt{x^2+z^2}}\right)}dx$

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score 122 · Answer 3 · 2026-03-22 07:46:30

122

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948

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score 68 · Answer 6 · 2026-03-22 21:47:26

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score 146 · Answer 7 · 2026-03-22 23:05:12

146

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score 73 · Answer 8 · 2026-03-23 07:46:41

73

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46

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1.3k

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score 114 · Answer 11 · 2026-03-23 03:49:07

114

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score 390 · Answer 12 · 2026-03-25 06:02:16

390

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score 129 · Answer 13 · 2026-03-25 01:18:13

129

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score 68 · Answer 14 · 2026-03-25 04:41:11

68

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score 91 · Answer 15 · 2026-03-25 06:05:32

91

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List Question

How to solve the integral equation $f(x) = \int_0^x f(x-y)k(x,y)dy+g(x)$ for $f(x)$?

Solving for $f\left(\sqrt{x^2+z^2}\right)$ given $g(z)=\int_{-\infty}^{+\infty}{\left(f\left(\sqrt{x^2+z^2}\right)\frac{1}{\sqrt{x^2+z^2}}\right)}dx$

Approximate solutions to nonlinear differential equations using an integral sequence

Solving an integral equation by Fourier transform

Composition of bounded linear operator and an inverse of a linear operator bounded?

Volterra equation of first kind

Solution to a Volterra integral equation

Solution to integral equation involving logarithms

Importance of compact operators for numerical approximation of integral equations?

Can integral equations be paired with linear regression to fit a double Gaussian regression?

Solve $f(x) = \lambda\int_0^\pi(x+y)f(y)\mathrm dy$

Solution of Differential equation as an integral equation

Show that the given map F is a contraction map & find a solution of F, if any.

Fredholm Integral Equation of First Kind with finite limits, 1-D

Cast the homogeneous Volterra equation into a first-order differential equation - Solutions are not the same

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