Question

The measure of a sequence of open sets

score 131 · Answer 1 · 2026-05-14 05:27:16

131

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The measure of a sequence of open sets

Published on 14 May 2026 - 5:27

score 183 · Answer 2 · 2026-05-11 07:51:34

183

Views

Intuition behind inequality for measure of $\liminf$ and $\limsup$

Published on 11 May 2026 - 7:51

score 82 · Answer 3 · 2026-04-15 08:22:13

82

Views

If $X$ and $Y$ are measurable, is $\left\{X=Y\right\}$ measurable?

Published on 15 Apr 2026 - 8:22

score 1.1k · Answer 4 · 2026-04-09 09:30:44

1.1k

Views

Counterexample in Radon-Nikodym Theorem. Problem 38 Royden 2ed.

Published on 09 Apr 2026 - 9:30

score 73 · Answer 5 · 2026-04-11 21:51:04

73

Views

Lebesgue integral on $[0,1]^{2}$

Published on 11 Apr 2026 - 21:51

score 96 · Answer 6 · 2026-05-10 17:33:16

96

Views

Interchanging limit and integral.

Published on 10 May 2026 - 17:33

score 38 · Answer 7 · 2026-04-14 02:58:39

38

Views

$X$ a numerable set, $f$ a positive function, then $\mu(A) = \sum_{x\in A} f(x)$ $\sigma$-finite?

Published on 14 Apr 2026 - 2:58

score 258 · Answer 8 · 2026-04-11 23:54:28

258

Views

How to use Lebesgue Dominated Convergence theorem in this example?

Published on 11 Apr 2026 - 23:54

score 225 · Answer 9 · 2026-04-15 13:08:43

225

Views

Dual space of $L^p(\Omega,\mathcal{A},\mu,\mathbb{R}^d)$.

Published on 15 Apr 2026 - 13:08

score 292 · Answer 10 · 2026-04-12 04:30:30

292

Views

A measurable set from a sequence of sets

Published on 12 Apr 2026 - 4:30

score 116 · Answer 11 · 2026-04-09 06:04:38

116

Views

Rewriting an integral of an absolutely continuous function

Published on 09 Apr 2026 - 6:04

score 68 · Answer 12 · 2026-04-16 10:38:00

68

Views

If $E$ open set. Why $\left\{(x,y):x-y\in E\right\}$ is Lebesgue measurable?

Published on 16 Apr 2026 - 10:38

score 338 · Answer 13 · 2026-05-14 09:03:59

338

Views

Do general discrete subgroups of $\operatorname{SL}_2(\mathbb R)$ have fundamental domains in the upper half plane?

Published on 14 May 2026 - 9:03

score 69 · Answer 14 · 2026-04-13 22:08:12

69

Views

Equivalent condition of a non-negative real-valued function on $[0,1]$ being measurable

Published on 13 Apr 2026 - 22:08

score 124 · Answer 15 · 2026-04-13 19:52:18

124

Views

A Borel set $E$ is a null set for the Borel measure that is induced by $\sigma(x)=x^2$ if and only if $E$ is a Lebesgue null set

Published on 13 Apr 2026 - 19:52

List Question

The measure of a sequence of open sets

Intuition behind inequality for measure of $\liminf$ and $\limsup$

If $X$ and $Y$ are measurable, is $\left\{X=Y\right\}$ measurable?

Counterexample in Radon-Nikodym Theorem. Problem 38 Royden 2ed.

Lebesgue integral on $[0,1]^{2}$

Interchanging limit and integral.

$X$ a numerable set, $f$ a positive function, then $\mu(A) = \sum_{x\in A} f(x)$ $\sigma$-finite?

How to use Lebesgue Dominated Convergence theorem in this example?

Dual space of $L^p(\Omega,\mathcal{A},\mu,\mathbb{R}^d)$.

A measurable set from a sequence of sets

Rewriting an integral of an absolutely continuous function

If $E$ open set. Why $\left\{(x,y):x-y\in E\right\}$ is Lebesgue measurable?

Do general discrete subgroups of $\operatorname{SL}_2(\mathbb R)$ have fundamental domains in the upper half plane?

Equivalent condition of a non-negative real-valued function on $[0,1]$ being measurable

A Borel set $E$ is a null set for the Borel measure that is induced by $\sigma(x)=x^2$ if and only if $E$ is a Lebesgue null set

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