Question

Behaviour of ${f}^{-1}$ under continuous map

score 42 · Answer 1 · 2026-03-26 06:10:33

42

Views

Behaviour of ${f}^{-1}$ under continuous map

Published on 26 Mar 2026 - 6:10

score 81 · Answer 2 · 2026-03-26 04:35:12

81

Views

Given a product topology X = $\prod_{i \in I}X_i$ , check: if E is closed in X, then $\pi_i(E)$ is closed in $X_i$

Published on 26 Mar 2026 - 4:35

score 75 · Answer 3 · 2021-07-01 09:44:09

75

Views

On Banach-Schauder theorem (open-mapping)

Published on 01 Jul 2021 - 9:44

score 96 · Answer 4 · 2021-07-21 16:07:00

96

Views

Is the mapping $\mathbb{R}^2 \to \mathbb{R} ^2$ given by $(\xi_1,\xi_2) \to (\xi_1,0) $ an open mapping ?Yes/No

Published on 21 Jul 2021 - 16:07

score 207 · Answer 5 · 2021-08-02 11:23:50

207

Views

Why can any homeomorphism on a topological space can be extended to its Čech-Stone compactification?

Published on 02 Aug 2021 - 11:23

score 198 · Answer 6 · 2021-09-19 06:48:19

198

Views

Is there an open bijective map from $\mathbb{R}$ to $\mathbb{R}$ that is not continuous?

Published on 19 Sep 2021 - 6:48

score 89 · Answer 7 · 2021-09-23 03:30:41

89

Views

Is $\varphi : \mathbb{R^2} -\{0\}\rightarrow S^1$ defined by $\varphi (x)=\frac{x}{|x|}$ a quotient map?

Published on 23 Sep 2021 - 3:30

score 193 · Answer 8 · 2021-09-29 23:34:04

193

Views

What is the difference between a continuous map and an identification map?

Published on 29 Sep 2021 - 23:34

score 99 · Answer 9 · 2021-09-30 11:31:13

99

Views

What is the difference between an identification and an open identification?

Published on 30 Sep 2021 - 11:31

score 59 · Answer 10 · 2021-10-02 02:54:50

59

Views

How to show this map is open?

Published on 02 Oct 2021 - 2:54

score 83 · Answer 11 · 2021-10-15 03:45:26

83

Views

For $f$ open and surjective, let $x \in X$ have a filter $F \to f(x)$. Then $\exists U$ a filter where $F \vdash f(U)$ and $f(U) \vdash F$.

Published on 15 Oct 2021 - 3:45

score 128 · Answer 12 · 2021-10-26 06:53:11

128

Views

A continuous open surjective map $f$ with compact fibers preserves Hausdorffness.

Published on 26 Oct 2021 - 6:53

score 331 · Answer 13 · 2021-11-02 20:20:41

331

Views

$T^*$ is surjective implies $T$ is bounded below.

Published on 02 Nov 2021 - 20:20

score 270 · Answer 14 · 2021-11-16 20:21:56

270

Views

Does a homeomorphism between metric spaces map open balls to open balls?

Published on 16 Nov 2021 - 20:21

score 79 · Answer 15 · 2021-11-24 14:42:03

79

Views

Is there such a mapping that is open mapping.

Published on 24 Nov 2021 - 14:42

List Question

Behaviour of ${f}^{-1}$ under continuous map

Given a product topology X = $\prod_{i \in I}X_i$ , check: if E is closed in X, then $\pi_i(E)$ is closed in $X_i$

On Banach-Schauder theorem (open-mapping)

Is the mapping $\mathbb{R}^2 \to \mathbb{R} ^2$ given by $(\xi_1,\xi_2) \to (\xi_1,0) $ an open mapping ?Yes/No

Why can any homeomorphism on a topological space can be extended to its Čech-Stone compactification?

Is there an open bijective map from $\mathbb{R}$ to $\mathbb{R}$ that is not continuous?

Is $\varphi : \mathbb{R^2} -\{0\}\rightarrow S^1$ defined by $\varphi (x)=\frac{x}{|x|}$ a quotient map?

What is the difference between a continuous map and an identification map?

What is the difference between an identification and an open identification?

How to show this map is open?

For $f$ open and surjective, let $x \in X$ have a filter $F \to f(x)$. Then $\exists U$ a filter where $F \vdash f(U)$ and $f(U) \vdash F$.

A continuous open surjective map $f$ with compact fibers preserves Hausdorffness.

$T^*$ is surjective implies $T$ is bounded below.

Does a homeomorphism between metric spaces map open balls to open balls?

Is there such a mapping that is open mapping.

Trending Questions

Popular # Hahtags

Popular Questions