Question

If $A:X \rightarrow X$ is a linear bounded operator then $e^{A}:X \rightarrow X$ is a linear bounded operator

score 92 · Answer 1 · 2026-04-12 08:33:23

92

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If $A:X \rightarrow X$ is a linear bounded operator then $e^{A}:X \rightarrow X$ is a linear bounded operator

Published on 12 Apr 2026 - 8:33

score 1k · Answer 2 · 2026-04-14 04:34:05

1k

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$f$ is continuous and of bounded variation on $[a,b]$, then $V[a,x]$ is continuous?

Published on 14 Apr 2026 - 4:34

score 98 · Answer 3 · 2026-04-16 03:54:29

98

Views

Let $a>b$ and $ab=1$ show that $\frac{a^2+b^2}{a-b} \geq 2\sqrt{2}$

Published on 16 Apr 2026 - 3:54

score 58 · Answer 4 · 2026-04-14 15:24:52

58

Views

Prove that in finite steps you can know if the solution set of linear programming problem is unbounded

Published on 14 Apr 2026 - 15:24

score 40 · Answer 5 · 2026-04-09 00:49:35

40

Views

induction proof manipulation problem

Published on 09 Apr 2026 - 0:49

score 52 · Answer 6 · 2026-04-14 05:16:05

52

Views

Prove $|A \times A| \geq |A|$

Published on 14 Apr 2026 - 5:16

score 79 · Answer 7 · 2026-04-24 03:02:26

79

Views

Derivative definition with double limit

Published on 24 Apr 2026 - 3:02

score 126 · Answer 8 · 2026-04-10 01:57:34

126

Views

Prove the existence of a one-to-one function for a recursive definition

Published on 10 Apr 2026 - 1:57

score 65 · Answer 9 · 2026-04-16 16:11:49

65

Views

Prove continuity by definition and epsilon-delta property. $g(x)=\sqrt{2x+1} , x_0=-0.5$

Published on 16 Apr 2026 - 16:11

score 135 · Answer 10 · 2026-04-12 17:09:28

135

Views

Help with a sequence proof

Published on 12 Apr 2026 - 17:09

score 2k · Answer 11 · 2026-03-31 05:38:55

2k

Views

Newton's method - optimal step size

Published on 31 Mar 2026 - 5:38

score 1.8k · Answer 12 · 2026-04-14 21:40:15

1.8k

Views

Proof: If $\lambda$ is an eigenvalue of $A$ and $x$ is a corresponding eigenvector, then $sAx=s\lambda x$ for every scalar $s$.

Published on 14 Apr 2026 - 21:40

score 282 · Answer 13 · 2026-04-14 05:14:00

282

Views

If the limit of a function exists as $x$ tends do infinity, must its derivative also exist?

Published on 14 Apr 2026 - 5:14

score 106 · Answer 14 · 2026-04-17 10:37:37

106

Views

Given $x^2=2$ prove for any rational number $\frac{p}{q} < x$,there exists $\frac{m}{n}$ such that $\frac{p}{q}<\frac{m}{n}<x$

Published on 17 Apr 2026 - 10:37

score 110 · Answer 15 · 2026-04-16 06:57:46

110

Views

If $∩F$ and $∩G$ are disjoint, then for some $A ∈ F$ and $B ∈ G$, $A$ and $B$ are disjoint.

Published on 16 Apr 2026 - 6:57

List Question

If $A:X \rightarrow X$ is a linear bounded operator then $e^{A}:X \rightarrow X$ is a linear bounded operator

$f$ is continuous and of bounded variation on $[a,b]$, then $V[a,x]$ is continuous?

Let $a>b$ and $ab=1$ show that $\frac{a^2+b^2}{a-b} \geq 2\sqrt{2}$

Prove that in finite steps you can know if the solution set of linear programming problem is unbounded

induction proof manipulation problem

Prove $|A \times A| \geq |A|$

Derivative definition with double limit

Prove the existence of a one-to-one function for a recursive definition

Prove continuity by definition and epsilon-delta property. $g(x)=\sqrt{2x+1} , x_0=-0.5$

Help with a sequence proof

Newton's method - optimal step size

Proof: If $\lambda$ is an eigenvalue of $A$ and $x$ is a corresponding eigenvector, then $sAx=s\lambda x$ for every scalar $s$.

If the limit of a function exists as $x$ tends do infinity, must its derivative also exist?

Given $x^2=2$ prove for any rational number $\frac{p}{q} < x$,there exists $\frac{m}{n}$ such that $\frac{p}{q}<\frac{m}{n}<x$

If $∩F$ and $∩G$ are disjoint, then for some $A ∈ F$ and $B ∈ G$, $A$ and $B$ are disjoint.

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