Question

Prove Ramanujan's formula for nested cubic roots $\sqrt[3]{{a}+b\sqrt[3]{r}}$

score 515 · Answer 1 · 2026-03-30 08:15:17

515

Views

Prove Ramanujan's formula for nested cubic roots $\sqrt[3]{{a}+b\sqrt[3]{r}}$

Published on 30 Mar 2026 - 8:15

score 47 · Answer 2 · 2017-05-10 20:14:53

47

Views

Expanding an expression of the form $(a \pm b)^{1/n}$

Published on 10 May 2017 - 20:14

score 36 · Answer 3 · 2026-04-11 10:26:24

36

Views

Design of exercises on assessing whether two expressions involving radicals are equal

Published on 11 Apr 2026 - 10:26

score 594 · Answer 4 · 2026-04-12 05:33:37

594

Views

Why can I not take the positive or negative square root while solving a quadratic equation in this instance?

Published on 12 Apr 2026 - 5:33

score 124 · Answer 5 · 2026-04-05 18:38:28

124

Views

Simplifying $\lim_{n\to \infty} \frac{\sqrt[n]{2}-1}{\sqrt[n]{8}-1}$

Published on 05 Apr 2026 - 18:38

score 677 · Answer 6 · 2026-03-29 22:25:13

677

Views

Proving Ramanujan's Nested Cube Root

Published on 29 Mar 2026 - 22:25

score 762 · Answer 7 · 2017-05-13 08:37:02

762

Views

To prove $\frac{1}{2} \times \frac{3}{4} \times \frac{5}{6} \cdots \frac{(2n-1)}{2n} \le \frac{1}{\sqrt{3n+1}}$

Published on 13 May 2017 - 8:37

score 112 · Answer 8 · 2026-04-01 22:34:49

112

Views

Show that $n + (\sqrt n)$ is not a perfect square

Published on 01 Apr 2026 - 22:34

score 131 · Answer 9 · 2017-05-13 19:34:36

131

Views

$\sqrt{x^2-x+1}+\sqrt{y^2-y+1}=\sqrt{x^2+xy+y^2}$

Published on 13 May 2017 - 19:34

score 141 · Answer 10 · 2026-04-11 20:12:01

141

Views

Two solutions for a given problem when simplifying double radicals?

Published on 11 Apr 2026 - 20:12

score 34 · Answer 11 · 2026-04-10 04:37:08

34

Views

maximal ideals of the Rad A

Published on 10 Apr 2026 - 4:37

score 135 · Answer 12 · 2026-04-11 03:37:30

135

Views

What does "$-2,25$ in $\mathbb{C}$" mean?

Published on 11 Apr 2026 - 3:37

score 84 · Answer 13 · 2026-04-12 02:16:17

84

Views

Solving radical equations

Published on 12 Apr 2026 - 2:16

score 173 · Answer 14 · 2026-04-09 06:06:23

173

Views

Quadratic Integers and Sandwich Numbers

Published on 09 Apr 2026 - 6:06

score 98 · Answer 15 · 2017-05-18 08:15:46

98

Views

Decide wether $x^6 + 2x^5 - 5x^4 - 5x^3 - 5x^2 + 2x + 1 = 0$ can be solved by radicals

Published on 18 May 2017 - 8:15

List Question

Prove Ramanujan's formula for nested cubic roots $\sqrt[3]{{a}+b\sqrt[3]{r}}$

Expanding an expression of the form $(a \pm b)^{1/n}$

Design of exercises on assessing whether two expressions involving radicals are equal

Why can I not take the positive or negative square root while solving a quadratic equation in this instance?

Simplifying $\lim_{n\to \infty} \frac{\sqrt[n]{2}-1}{\sqrt[n]{8}-1}$

Proving Ramanujan's Nested Cube Root

To prove $\frac{1}{2} \times \frac{3}{4} \times \frac{5}{6} \cdots \frac{(2n-1)}{2n} \le \frac{1}{\sqrt{3n+1}}$

Show that $n + (\sqrt n)$ is not a perfect square

$\sqrt{x^2-x+1}+\sqrt{y^2-y+1}=\sqrt{x^2+xy+y^2}$

Two solutions for a given problem when simplifying double radicals?

maximal ideals of the Rad A

What does "$-2,25$ in $\mathbb{C}$" mean?

Solving radical equations

Quadratic Integers and Sandwich Numbers

Decide wether $x^6 + 2x^5 - 5x^4 - 5x^3 - 5x^2 + 2x + 1 = 0$ can be solved by radicals

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