Question

Proof that $ \frac {2\pi} {k} $ is the period of $ y=\sin(kx) $

score 1.3k · Answer 1 · 2018-11-04 12:15:01

1.3k

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Proof that $ \frac {2\pi} {k} $ is the period of $ y=\sin(kx) $

Published on 04 Nov 2018 - 12:15

score 74 · Answer 2 · 2026-04-12 17:21:36

74

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Solving a right triangle (Trigonometry)

Published on 12 Apr 2026 - 17:21

score 122 · Answer 3 · 2026-04-11 09:49:49

122

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Closed-form solution of trigonometric equation

Published on 11 Apr 2026 - 9:49

score 108 · Answer 4 · 2026-04-12 20:50:52

108

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Find a line along a circle's perimeter?

Published on 12 Apr 2026 - 20:50

score 2.3k · Answer 5 · 2026-04-11 05:46:55

2.3k

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How do calculators calculate the value of trigonometric functions?

Published on 11 Apr 2026 - 5:46

score 54 · Answer 6 · 2026-03-25 17:20:11

54

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If $\sin(\beta+\gamma)= \sin\epsilon$ and $\cos\beta\cos\gamma<\sin\beta\sin\gamma$, then $\beta+\gamma=\pi-\epsilon$

Published on 25 Mar 2026 - 17:20

score 69 · Answer 7 · 2018-11-05 09:11:19

69

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How is the trig identity $\tan^2(x) = \sec^2(x) -1$ derived?

Published on 05 Nov 2018 - 9:11

score 217 · Answer 8 · 2026-04-10 16:30:35

217

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Solving $\sin x = \sin y$ by using the prosthaphaeresis formulas

Published on 10 Apr 2026 - 16:30

score 156 · Answer 9 · 2026-03-26 17:52:45

156

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How do I prove that $\lim_{x\to \infty} |\cos x|^x$ doesn't exist?

Published on 26 Mar 2026 - 17:52

score 142 · Answer 10 · 2026-04-09 12:18:41

142

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Proof of $tangent$ definition

Published on 09 Apr 2026 - 12:18

score 50 · Answer 11 · 2026-04-09 03:37:06

50

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Calculating Sums Of Maths

Published on 09 Apr 2026 - 3:37

score 81 · Answer 12 · 2026-04-12 20:53:56

81

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Find angle of line along a circle's perimeter?

Published on 12 Apr 2026 - 20:53

score 203 · Answer 13 · 2026-04-12 23:33:33

203

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The second solution of $\sin\left(x\right)=\cos\left(2x\right)$

Published on 12 Apr 2026 - 23:33

score 221 · Answer 14 · 2026-04-02 01:05:42

221

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Calculate $\sum_{n=1}^{\infty} \arctan\bigl(\frac{2\sqrt2}{n^2+1}\bigr) $

Published on 02 Apr 2026 - 1:05

score 139 · Answer 15 · 2018-11-06 21:04:14

139

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Area bounded by $y=\sqrt{\frac{1+\sin{x}}{\cos{x}}}$ and $y=\sqrt{\frac{1-\sin{x}}{\cos{x}}}$

Published on 06 Nov 2018 - 21:04

List Question

Proof that $ \frac {2\pi} {k} $ is the period of $ y=\sin(kx) $

Solving a right triangle (Trigonometry)

Closed-form solution of trigonometric equation

Find a line along a circle's perimeter?

How do calculators calculate the value of trigonometric functions?

If $\sin(\beta+\gamma)= \sin\epsilon$ and $\cos\beta\cos\gamma<\sin\beta\sin\gamma$, then $\beta+\gamma=\pi-\epsilon$

How is the trig identity $\tan^2(x) = \sec^2(x) -1$ derived?

Solving $\sin x = \sin y$ by using the prosthaphaeresis formulas

How do I prove that $\lim_{x\to \infty} |\cos x|^x$ doesn't exist?

Proof of $tangent$ definition

Calculating Sums Of Maths

Find angle of line along a circle's perimeter?

The second solution of $\sin\left(x\right)=\cos\left(2x\right)$

Calculate $\sum_{n=1}^{\infty} \arctan\bigl(\frac{2\sqrt2}{n^2+1}\bigr) $

Area bounded by $y=\sqrt{\frac{1+\sin{x}}{\cos{x}}}$ and $y=\sqrt{\frac{1-\sin{x}}{\cos{x}}}$

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