Question

A weakly open subset of the unit ball of the Read's space $R$ (an infinite-dimensional Banach space) is unbounded.

score 85 · Answer 1 · 2026-03-22 12:29:59

85

Views

A weakly open subset of the unit ball of the Read's space $R$ (an infinite-dimensional Banach space) is unbounded.

Published on 22 Mar 2026 - 12:29

score 84 · Answer 2 · 2026-03-23 07:27:57

84

Views

Deriving a particular Poincare equality by a lemma

Published on 23 Mar 2026 - 7:27

score 68 · Answer 3 · 2026-03-17 13:12:56

68

Views

$L^2$ convergence given weak $L^2$ convergence

Published on 17 Mar 2026 - 13:12

score 5.3k · Answer 4 · 2026-03-22 12:55:55

5.3k

Views

Definition of weak $L^p$ spaces

Published on 22 Mar 2026 - 12:55

score 510 · Answer 5 · 2026-03-23 03:47:21

510

Views

How to show that $C^\infty_0$ is not dense in $L^p_{weak} (\mathbb{R}^n)$?

Published on 23 Mar 2026 - 3:47

score 402 · Answer 6 · 2026-03-22 22:32:09

402

Views

Embedding $L^p$ into weak $L^p$ and notion of boundary of $L^p$

Published on 22 Mar 2026 - 22:32

score 101 · Answer 7 · 2026-03-23 06:42:23

101

Views

A proposition about bounded and weak-$L^2$ integrable fucntion

Published on 23 Mar 2026 - 6:42

score 196 · Answer 8 · 2026-03-22 22:16:26

196

Views

Weak Star Convergence of $u_n=\sin(\frac{nx}{n+1})(1+\exp{(-n|y|)})$

Published on 22 Mar 2026 - 22:16

score 29 · Answer 9 · 2026-03-22 09:34:35

29

Views

Counting Balls in $L^2_m[0,1]$

Published on 22 Mar 2026 - 9:34

score 378 · Answer 10 · 2026-03-23 07:10:22

378

Views

$L^{q,\infty}(\mu) \subset L^p(\mu)$ with $1 \leq p<q <\infty$ and $\mu$ finite measure?

Published on 23 Mar 2026 - 7:10

score 59 · Answer 11 · 2026-03-22 13:56:54

59

Views

If we have a sequence of measurable functions that is Cauchy with respect to the weak L^p norm, is it Cauchy with respect to the L^p norm?

Published on 22 Mar 2026 - 13:56

score 491 · Answer 12 · 2026-03-24 23:45:02

491

Views

How can I prove that the Hilbert transform on the 1-torus doesn't map $L^1(\mathbb{T})$ into itself?

Published on 24 Mar 2026 - 23:45

score 209 · Answer 13 · 2026-03-25 06:43:35

209

Views

Show that $g_n(x)=ne^{-nx}$ is bounded, where $x\in\Omega=]0,1[$ for $n\in\Bbb{N}.$

Published on 25 Mar 2026 - 6:43

score 625 · Answer 14 · 2026-03-22 05:32:19

625

Views

normal distribution and weak convergence

Published on 22 Mar 2026 - 5:32

score 1.2k · Answer 15 · 2026-03-16 23:45:17

1.2k

Views

Reference concerning weak-type (1,1) operator in $\mathbb{R}^d$

Published on 16 Mar 2026 - 23:45

List Question

A weakly open subset of the unit ball of the Read's space $R$ (an infinite-dimensional Banach space) is unbounded.

Deriving a particular Poincare equality by a lemma

$L^2$ convergence given weak $L^2$ convergence

Definition of weak $L^p$ spaces

How to show that $C^\infty_0$ is not dense in $L^p_{weak} (\mathbb{R}^n)$?

Embedding $L^p$ into weak $L^p$ and notion of boundary of $L^p$

A proposition about bounded and weak-$L^2$ integrable fucntion

Weak Star Convergence of $u_n=\sin(\frac{nx}{n+1})(1+\exp{(-n|y|)})$

Counting Balls in $L^2_m[0,1]$

$L^{q,\infty}(\mu) \subset L^p(\mu)$ with $1 \leq p<q <\infty$ and $\mu$ finite measure?

If we have a sequence of measurable functions that is Cauchy with respect to the weak L^p norm, is it Cauchy with respect to the L^p norm?

How can I prove that the Hilbert transform on the 1-torus doesn't map $L^1(\mathbb{T})$ into itself?

Show that $g_n(x)=ne^{-nx}$ is bounded, where $x\in\Omega=]0,1[$ for $n\in\Bbb{N}.$

normal distribution and weak convergence

Reference concerning weak-type (1,1) operator in $\mathbb{R}^d$

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