Help me evaluate this equation in Scientific Notation

Question

How do i solve this using Scientific Notation? $$ \frac{3\times 10^8}{4\times 10^{-5}} $$
I have been trying for hours now! Help please

Answer 1

$$\dfrac {a^c}{a^d} = a^{c-d}$$

So your fraction is $$\frac{3\times 10^8}{4\times 10^{-5}} = \dfrac 34\times 10^{8 - (-5)} = \dfrac 34 \times 10^{13} = 0.75\times 10^{13}= 7.50 \times 10^{12}$$

Answer 2

First note that $$ \frac{x^a}{x^{-b}}= \frac{x^a}{\frac{1}{x^{b}}}=x^ax^b =x^{a+b}, \quad x\not =0$$ So now $$ \frac{3\times 10^8}{4\times 10^{-5}}= \frac{3}{4}\times \frac{10^8}{10^{-5}}= \frac{3}{4}\times 10^8\times 10^5 $$ $$= 0.75\times 10^{8+5}= 0.75\times 10^{13}=7.5\times 10^{12}$$