could anyone help in validating this absolute value question that my son is working on? $|(|x-3|-2)|\leq 1$
$-1\leq|x-3|-2\leq 1$
$1\leq|x-3|\leq 3$
$1\leq x-3\leq 3$
$4\leq x\leq 6$
or
$-3\leq x-3\leq -1$
$0\leq x\leq 2$
thus
$x\in [4,6]\cup [0,2]$
2026-04-06 13:06:54.1775480814
help with absolute value question $||x-3|-2|\leq 1$
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