Let $$B = \begin{bmatrix} 1 & 2 & 3 \\ 1 & 1 & 1 \\ 1 & 3 & 5 \end{bmatrix} $$ and $$C = \begin{bmatrix} 1 & 3 & 5 \\ 1 & 2 & 3 \\ 1 & 1 & 1 \end{bmatrix}. $$
Find a matrix $A$ that satisfies the equation AB = C. I tried to do A = C*B^(-1) but found the determinant is 0 for B. Is there another way to solve this?
Use row-operations on $B^\top A^\top = C^\top$.
Since $B$ is singular, there is no guarantee that the equation has a solution (it will depend on the columns of $C^\top$).