I am currently working on final project with WASPAS procedure where the determination of lambda include Π in the calculation. Does anyone could help to solve this equation? I have tried for more than an hour and still havent figure it out.
$\sigma^2(x_{ij})= (0.05x_{ij})^2$
The example in the journal for the data is this $w_1 = 0.467$ $w_2= 0.160$ $w_3= 0.095$ and $w_4 = 0.278$ $x_{11} = 0.837$ $x_{12}= 0.8389$ $x_{13}= 1$ and $x_{14}= 0.8594$
using only these $8$ data it could obtain the $\sigma^2(Q_i)^2 =0.8578$ I still have no idea how to use the equation to obtain that number.
Your help will be very appreciated! I still could not copy an image as my point is below $10$, please kindly click the link to see the equation