I have the following equation:
$B^{-1}E^{-1}(B^{-1}R^{-1}BE)^{\frac{1}{2}}B=Q$
B, E,R and Q are all square, reversible matrices.
I need to find an expression for B.
any ideas?
I have the following equation:
$B^{-1}E^{-1}(B^{-1}R^{-1}BE)^{\frac{1}{2}}B=Q$
B, E,R and Q are all square, reversible matrices.
I need to find an expression for B.
any ideas?
I assume that your matrices are real. If you want to obtain solutions in $B$, then necessarily, $\det(R)(\det(Q))^2\det(E)=1, \det(E)\det(Q)>0$.
Moreover, when solutions exist, there is an infinity; for example, when $n=2$, in general, the degree of freedom is $1$.
Of course, there does not exist any closed form for the solutions.