Let $n\in\mathbf{N}$ and $\lambda=(\lambda_1,\ldots,\lambda_\ell)$ be integers such that $\sum_{i=1}^\ell\lambda_i=n$. To this partition consider the Schur-Polynomial $s_\lambda$. When expressed in terms of monomial symmetric function, we have $s_\lambda=\sum_{\mu\vdash n} K_{\lambda,\mu} m_\mu$, where $\mu$ runs through all partitions of $n$. The coefficients $K_{\lambda,\mu}$ are the so called Kostka numbers. My questions is: How big can these numbers be?
2026-03-26 16:10:48.1774541448
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How big are Kostka-Numbers
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FYI you can get the Kostka numbers with the R package jack:
> KostkaNumbers(6)
(6) (5,1) (4,2) (4,1,1) (3,3) (3,2,1) (3,1,1,1) (2,2,2) (2,2,1,1) (2,1,1,1,1) (1,1,1,1,1,1)
(6) 1 1 1 1 1 1 1 1 1 1 1
(5,1) 0 1 1 2 1 2 3 2 3 4 5
(4,2) 0 0 1 1 1 2 3 3 4 6 9
(4,1,1) 0 0 0 1 0 1 3 1 3 6 10
(3,3) 0 0 0 0 1 1 1 1 2 3 5
(3,2,1) 0 0 0 0 0 1 2 2 4 8 16
(3,1,1,1) 0 0 0 0 0 0 1 0 1 4 10
(2,2,2) 0 0 0 0 0 0 0 1 1 2 5
(2,2,1,1) 0 0 0 0 0 0 0 0 1 3 9
(2,1,1,1,1) 0 0 0 0 0 0 0 0 0 1 5
(1,1,1,1,1,1) 0 0 0 0 0 0 0 0 0 0 1
They grow very fast, except for very restrictive shapes. For example, if $\mu=(1,\cdots,1)$ then the Kostka numbers reduce to numbers of Standard Young tableau of shape $\lambda$. Keeping $\mu=(1,1,\cdots,1)$, if $\lambda=(n,0,\cdots,0)$, the Kostka number is always always 1.
Using hook formulas, and Stirling's formula you can get for example that the number of standard staircase shaped Young tableau with shape $\lambda=(n-1,n-2,\cdots,1)$ grows something like $\exp(n^2\log(n)/2)\approx n^{n^2/2}$, meaning that past around $n=10$ the number exceeds the estimated number of atoms in the known universe ($\approx 10^{50}$).