Find the point of intersection between $f(x) = x^3$ and $g(x) = x^{1/3}$
Once I equal each equation to each other, I could factor out the $x$ but the exponent 1/3 is confusing me.
Thank you!
Set $f = g$, $$x^3 = x^{\frac{1}{3}} \Rightarrow (x^3)^3 = (x^{\frac{1}{3}})^3 \Rightarrow x^9 = x$$ $$\Rightarrow x^9 -x = x(x^8-1) = x(x-1)(x+1)(x^2+1)(x^4+1) = 0$$
So your roots are $$x = 0$$ $$x =\pm 1$$
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Set $f = g$, $$x^3 = x^{\frac{1}{3}} \Rightarrow (x^3)^3 = (x^{\frac{1}{3}})^3 \Rightarrow x^9 = x$$ $$\Rightarrow x^9 -x = x(x^8-1) = x(x-1)(x+1)(x^2+1)(x^4+1) = 0$$
So your roots are $$x = 0$$ $$x =\pm 1$$