Sorry for such a simple question.
I have $y\ln(5) = 2\ln 3$
And I wanted to know if I can solve for $y$ by just dividing the logarithm on both sides?
So I would get $y = \frac {2\ln 3}{\ln(5)} = 2 \ln 3 - \ln 5$
Sorry for such a simple question.
I have $y\ln(5) = 2\ln 3$
And I wanted to know if I can solve for $y$ by just dividing the logarithm on both sides?
So I would get $y = \frac {2\ln 3}{\ln(5)} = 2 \ln 3 - \ln 5$
To more directly answer your question, yes, you can divide both sides by $\ln(5)$ to isolate $y$.
However also as pointed out in other posts, you're mixing up properties. $\ln(a/b) = \ln(a)-\ln(b)$ - it's not $\ln(a)/\ln(b)=\ln(a)-\ln(b)$. For an easy way to see this, take $a=b=1$. Then
$$\ln\left( \frac 1 1 \right) = \ln(1) = 0 = 0 - 0 = \ln(1) - \ln(1)$$
but
$$\frac{\ln(1)}{\ln(1)} = \frac 0 0 \ne \ln(1) - \ln(1) = 0$$