i don't understand this at all. how can i deduct if a student was at the campus?
EDIT: i tried to convert all of the following into a first order logic in a closed domain (and some closed world assumptions) to better understand the subject, i.e: if we know that Helen is a professor, then only helen is a professor can be inferred from the statement).
sorry for the change, but it is very important for me to do it like this so i can learn it correctly and methodically. i also tried to put the sentences into first order logic like i asked here
i know that:
- every professor counsels at least one student
$\forall x,y(C(x,y) \land \forall x,y -> (x=p \land y=(\exists S(s)))$
- Helen is a professor
$\exists x(P(x) \land x-> x='Helen')$
- every student has a counselor, who is a professor
$\forall x,y(H(x,y) \land \forall x,y(x=s \land y=c) \land c -> p)$
- counseling meeting occur at the campus
$\exists x,y(occurs(x,y) \land \forall x,y ((x=m \land i) \land y = u)$
- Leno is a student
$\exists x(S(x) \land x -> x= s)$
- every counselor meets with all of his counselees(the ones he counsels)
$\forall x,y(M(x,y) \land x=c \land M(x,y) -> y=h )$ (a counselor meets with all of his counselees, and if he meets someone it must be his counselee)
where:
S(x) - x is a student
P(x) - x is a professor
C(x,y) - x counsels y
M(x,y) - x meets with y
O(x,y) - x occurs at y
H(x,y) - x has y
p - a professor
s - a student
c - a counselor
m - a meeting
h - a counselee
i - a counseling
u - a campus
i don't understand, how can i conclude if helen was at the campus or not?
please help me with that and explain so i can learn and apply what you do on about a dozen more i've got. they had not taught us this well
edit: to make more sense, at least for me, i am trying to "formalize" the given sentences using first order logic to make it simpler, i am hoping the formalization would be correct.
Let $P$ be the set of all professors, and $S$ the set of all students. You can then interperet the statements as follows:
(1) For all $p\in P$, there exists an $s\in S$ such that $p$ counsels $s$. We can term this statement $C$ for 'counsels' and write it symbolically as...
$$\forall p\in P.\exists s\in S:C(p,s)$$
(2) There exists a $p\in P$ such that $p=$Helen. Symbollically...
$$\exists p\in P:p=\text{Helen}$$
or, more succinctly...
$$\text{Helen}\in P$$
(3) For all $s\in S$, there exists a $p\in P$ such that $p$ counsels $s$. Symbollically... $$\forall s\in S.\exists p\in P:C(p,s)$$
(4) Counseling meetings occurs on campus. We can denote 'counseling occurs on campus' with $L$ for 'location'.
(5) There exists an $s\in S$ such that $s=$Leno. Symbollically...
$$\exists s\in S:s=\text{Leno}$$
or, more succinctly...
$$\text{Leno}\in S$$
(6) For all $p\in P$, there exists a subset $S_p\subseteq S$ such that for all $s\in S_p$, $p$ meets with $S$. We may denote '$p$ meets with $s$' by $M$ for 'meeting. Symbollically...
$$\forall p\in P.\exists S_p\subseteq S:(\forall s\in S_p.M(p,s))$$
Let $K(p,s)\equiv\text{$p$ and $s$ are on campus}$.
We want to show that there is some $s$ such that $K(\text{Helen},s)$ is true.
It is clear that $C(p,s)\land L\land M(p,s)\implies K(p,s)$ - if $p$ counsels $s$ and all counseling meetings are on campus, and $p$ meets with $s$, then, at some point, $p$ and $s$ must both be on campus. From (2), we know that Helen is a professor and from (1) we know that all professors counsel at least one student. The conjunction of (1) and (2) then implies that there is a student $s$, such that $C(\text{Helen},s)$. Likewise, from (6), we know that $M(\text{Helen},s)$ must be true. Finally, $C(\text{Helen},s)\land L\land M(\text{Helen},s)\implies K(\text{Helen},s)$ ($L$ is always true). Therefore, at some point Helen must be on campus.
Symbolic:
$$Q:=\text{Helen}\in P\land(\forall p\in P.\exists s\in S:C(p,s))\implies \exists s\in S:C(\text{Helen},s)$$
$$U:=\text{Helen}\in P\land(\forall p\in P.\exists S_p\subseteq S:(\forall s\in S_p.M(p,s)))\implies \exists S_{\text{Helen}}\subseteq S:(\forall s\in S_{\text{Helen}}:M(\text{Helen},s))$$
$$R:=Q\land U\implies \exists s\in S:(C(\text{Helen},s)\land M(\text{Helen},s))$$
$$L\equiv\top$$
$$R\land L\implies \exists s\in S:K(\text{Helen},s)$$
(I would appreciate if someone could double check this)