Show that $$\prod_{k=1}^{m-1} \cot(\frac{k\pi}{2m}) = 1,$$ where $m$ is an integer greater than 1
I think it can be solved by nth root theorem but I don't get the answer :c
2026-04-03 14:27:12.1775226432
How can i show $\prod_{k=1}^{m-1} \cot(\frac{k\pi}{2m}) = 1$ where $m$ is an integer greater than 1
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Use $$\tan{x}\cot{x}=1$$ and $$\tan{x}=\cot\left(\frac{\pi}{2}-x\right).$$ I think it should help.