This is what I could come up with:
$\dfrac{2x}{\sqrt{1-x^2}}=0$
$\left(\dfrac{2x}{\sqrt{1-x^2}}\right)^2=0^2$
$\dfrac{4x^2}{1-x^2}=0$
I can't go forward from this point because of that stupid 0! Any help is appreciated!
This is what I could come up with:
$\dfrac{2x}{\sqrt{1-x^2}}=0$
$\left(\dfrac{2x}{\sqrt{1-x^2}}\right)^2=0^2$
$\dfrac{4x^2}{1-x^2}=0$
I can't go forward from this point because of that stupid 0! Any help is appreciated!
Hints:
$$\text{For any well-defined algebraic fraction}\;\;\frac ab\;,\;\;\text{we have that}\;\frac ab=0\iff a=0$$