I am trying to find a way to prove this, so far I have only gotten to
$x^4 + 1 ≥ x^3 + x$
Could you please help me?
It is enough to prove that
$$ x^4-x^3-x+1\geq 0. $$
We have
$$x^4-x^3-x+1=x^3(x-1)-(x-1)=(x-1)(x^3-1)=(x-1)^2(x^2+x+1).$$
Both factors are nonnegative for any positive real $x$ so the relation above holds true.
Subtract $2x^2$ from your last inequality, then $$ \iff (x^2-1)^2\ge x(x-1)^2\iff (x+1)^2\ge x\iff (2x+1)^2+3\ge0 $$ and the last is certainly true.
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It is enough to prove that
$$ x^4-x^3-x+1\geq 0. $$
We have
$$x^4-x^3-x+1=x^3(x-1)-(x-1)=(x-1)(x^3-1)=(x-1)^2(x^2+x+1).$$
Both factors are nonnegative for any positive real $x$ so the relation above holds true.