How "commutative" is matrix multiplication with identity matrices?

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A property of matrix multiplication is that, if $A$ & $B$ & $C$ are matrices

  • $A(BC) = (AB)C$ (associative)
  • $A(B+C)$ = $AB + AC$ and $(A + B)C = AC + BC$ (distributive)
  • $AB ≠ BA$ (not commutative)

And if $A$ is invertible and $AB=I$, then $BA=I$, hence B is the inverse of A, then:

$AB = I$

$A^{-1}AB = A^{-1}I$

$IB = A^{-1}I$

$B = A^{-1}$

$BA = A^{-1}A = I$

and I want to find X - an unknown matrix. This is true:

$AX = C $

$A^{-1} AX = A^{-1} C$

$IX = A^{-1}C$

$X = A^{-1} C$

But is the below variation also correct according to the matrix definitions and why? Does it matter where $A^{-1}$ is on the RHS, before or after $C$? Does it make a difference if $I$ is before or after $X$? The matrix definition says it is not commutative so the output is $IX ≠ XI$?

$XA = C$

$XAA^{-1} = CA^{-1}$

$XI = CA^{-1}$

$X = CA^{-1}$