So I have:
$$ \log_2(5x) + \log_2 3 + \frac{\log_2 10}{2} $$
I understand that when there is addition, and the bases are the same, I can simply multiply what is in the parenthesis. So for the first part, I'd get $\log_2(15x)$. I'm stuck now, because I'm not sure what to do with the third log term, since the entire thing is being divided by two.
You may write $$ \log_2(15x)+\frac12 \log_2(10)=\log_2(15x)+\log_2(10^{1/2})=\log_2(15x \cdot10^{1/2}). $$