How do I solve this equation for $t$?

Question

$$ \frac{48}{4^{-t}+2} = 0 $$

Apparently, when I graph it, it has a horizontal asymptote at $0$. How do I find the solution?

Thank you

Answer 1

Analysing the expression

$$\frac{48}{4^{-t}+2}$$

the most we can have is make $t\to -\infty$ and then we get

$$\frac{48}{4^{-t}+2}\to 0$$

but we will never reach $0$.