I need to compute the inverse Laplace transform $$\mathcal{L}^{-1}\Big[\frac{3}{(s^2+3)^2}\Big].$$ I already know that the answer is $$ \frac{1}{2\sqrt{3}}\Big(\sin(\sqrt{3}t)-\sqrt{3}t\cos(\sqrt{3}t)\Big),$$ but I don't understand how to get it. I appreciate any help, thanks!
2026-04-05 12:08:35.1775390915
How do you calculate inverse Laplace transform of a fraction
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