Suppose we have a function $y(x)$ such that
$y (\frac{-e^{-2\lambda} + e^{-\lambda}}{1-e^{-2\lambda}}) = \lambda$
How can I determine $y(x)$? Are there steps that outline how to solve such a problem? If so, could somebody point me to them?
For example, an easy scenario is find $g(x)$ such that $g(\frac{1}{\lambda})=\lambda$. Obviously $g(x)=\frac{1}{x}$. But this is easy and I didn't have to do much to realize what $g(x)$ is. However, in the problem above it's more complicated.
$$y(x)=\log\left(\frac1x-1\right)\qquad x\in(0,1)$$