I asked a similar question not too long ago, however after I posted it, I realized I accidentally put 4x and not 4y, so I apologize for the previous post. I am working on ODE and can't figure out how to do it without complex roots. Supposedly, I am to solve as above, where =∫d/.However, when I set up the equation, I am stumped on how to solve. I would appreciate the help! Thank you!
2026-03-29 18:57:09.1774810629
How do you solve $y''+4y=0$ using $='$ and $(d/d)=''$?
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HINT
Here it is another possible approach: \begin{align*} y'' + 4y = 0 & \Longleftrightarrow y''y' + 4yy' = 0\\\\ & \Longleftrightarrow (2y''y') + 4(2yy') = 0\\\\ & \Longleftrightarrow (y')^{2} + 4y^{2} = k \end{align*} where $k\geq 0$.
Can you take it from here?