How do you use partial fraction decomposition to break up $1/(s+4)^2$?
The usual method isn't giving me an answer.
Hint: You have a double root. The equation is
$$f(s)=\frac{1}{(s+4)^2}=\frac{A}{(s+4)}+\frac{B}{(s+4)^2}$$
Now it is easy to calculate A and B.
Remark:
If you want to integrate $f(s)$, you don't need to look for partial fractions.
$\int \frac{1}{(s+4)^2} \ dx=\int (s+4)^{-2} \ dx=-(s+4)^{-2+1}+C$
You are already done. You would write $\frac 1{(s+4)^2}=\frac A{s+4}+\frac B{(s+4)^2}$. Clearly $A=0, B=1$ is the solution.
The unicity of partial fraction decomposition gives the answer: it is $\;\dfrac1{(s+4)^2}$.
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Hint: You have a double root. The equation is
$$f(s)=\frac{1}{(s+4)^2}=\frac{A}{(s+4)}+\frac{B}{(s+4)^2}$$
Now it is easy to calculate A and B.
Remark:
If you want to integrate $f(s)$, you don't need to look for partial fractions.
$\int \frac{1}{(s+4)^2} \ dx=\int (s+4)^{-2} \ dx=-(s+4)^{-2+1}+C$