How does this case of the substitution rule of integration work?

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Picture of the integration step

I found the integration step shown in the picture in a book on quantum mechanics and I really don't understand how it works.

It has to be some magic trick using substitution.

I would solve it using integration by parts, is there any problem with that?

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The "magic trick" is "differentiation"!

To find $\frac{\partial^2 e^{-2\lambda x}}{\partial\lambda^2}$, differentiate twice. I presume that you know that the derivative of $e^{a\lambda}$, with respect to $\lambda$, is $ae^{a\lambda}$. Here, $a= -2x$ so the first derivative is $(-2x)e^{-2\lambda x}$. Then the second derivative just does that again: $(-2x)(-2x)e^{-2\lambda x}= 4x^2e^{-2\lambda x}$.

$x^2e^{-2\lambda x}= \frac{1}{4}(4x^2e^{-2\lambda x})$ and they have simply replaced $4x^2e^{-2\lambda x}$ by $\frac{\partial^2 e^{-2\lambda x}}{\partial\lambda^2}$ which is equal to it.