How is the expectation of the owner's payoff derived

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A prospector owns a gold mine where he can dig to recover gold. His output depends on the amount of gold in the mine, denoted by $x$. The prospector knows the value of $x$, but the rest of the world knows only that the amount of gold is uniformly distributed on the interval $[0,1]$. Before deciding to mine, the prospector can try to sell his mine to a large mining company, which is much more efficient in its extraction methods.The prospector can ask the company owner for any price $p≥0$, and the owner can reject (R) or accept (A) the offer. If the owner rejects the offer then the prospector is left to mine himself, and his payoff from self-mining is equal to $3x$. If the owner accepts the offer then the prospector’s payoff is the price $p$, while the owner’s payoff is given by the net value $4x-p$, and this is common knowledge.

(a) Show that for a given price $p≥0$ there is a threshold type $x(p)∈[0,1]$ of prospector, such that types below $x(p)$ will prefer to sell the mine,while types above $x(p)$ will prefer to self-mine.

(b) Find the pure strategy Bayesian Nash equilibrium of this game. What is the expected payoff of each type of prospector and of the company owner in the equilibrium you derived?

Here is the answer for (a), which i understand:

Given price $p$, the prospector of type $x$ is only willing to sell if $p >3x$ which implies $x<p/3$. Thus prospectors that are below type $x(p)=p/3$ will prefer to sell,while those above will prefer to self-mine.

And for (b), I don;t understand the value of the expected amount of gold from the owner's point of view:

Answer for (b):

(b) Note that the owner knows that given any price,$x$ must have been equal to $p/3$ or less. Given this, the expected amount of gold from the owner’s point of view is

$$E(x)=\frac{0+p/3)}{2}=p/6$$

Why is this so? I don't exactly understand how this is derived.